Melissa walks 3 miles to the house of a friend and returns home on a bike. She averages 4 miles per hour faster when cycling than when walking, and the total time for both trips is two hours. Find her walking speed.

Answer:s₁ = 2 m/sStep-by-step explanation:given,distance between Melissa and friend = 3 milewalking speed = s₁bike speed = s₂total time of the trip = 2 hourgiven,s₂ = s₁ + 4[tex]time =\dfrac{distance}{speed}[/tex][tex]t =\dfrac{3}{s_1} +\dfrac{3}{s_2}[/tex][tex]2 =\dfrac{3}{s_1} +\dfrac{3}{s_1+4}[/tex]2(s₁ +4)s₁ = 3 (s₁ + s₁ + 4)2 s₁² + 8 s₁ = 6 s₁ + 12s₁² + s₁ - 6 = 0s₁² + 3 s₁ - 2 s₁ - 6 = 0(s₁ + 3) (s₁ -2) = 0s₁ = -3 , 2s₁ = 2 m/swalking speed of the Melissa is s₁ = 2 m/s