SUPER EASY//////At a game show, there are 6 people (including you and your friend) in the front row. The host randomly chooses 3 people from the front row to be contestants. The order which they are chosen does not matter. How many ways can you and your friend both be chosen?
Accepted Solution
A:
Answer:20Premutation: Order matters.Combination: order doesn't matter. [tex]combination(n, r)=\frac{n!}{(n-r)!*r!}[/tex]n=6r=3[tex]\frac{6!}{(6-3)!*3!}=\frac{720}{3!*3!}=\frac{720}{6*6}=\frac{720}{36}=20[/tex]Hope this helps!!!